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Math Help - Can you help me check my equation?

  1. #1
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    Can you help me check my equation?

    Just need to check...did I do anything wrong? I think it's wrong, but just please help me check!

    Problem: A confectioner has candy costing 55 cents and 75 cents per kilogram. If he wishes to make 1000 kilograms of a mixture and sell it for 60 cents per kilogram, how much of each does he need?

    55x + 75(1000-x) = 60(1000)
    55x + 75 000 - 75x = 60 000
    -20x = -15 000
    x = 750

    Just checking! Thanks!
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by nathan02079 View Post
    Just need to check...did I do anything wrong? I think it's wrong, but just please help me check!

    Problem: A confectioner has candy costing 55 cents and 75 cents per kilogram. If he wishes to make 1000 kilograms of a mixture and sell it for 60 cents per kilogram, how much of each does he need?

    55x + 75(1000-x) = 60(1000)
    55x + 75 000 - 75x = 60 000
    -20x = -15 000
    x = 750

    Just checking! Thanks!
    looks fine, good job. but you haven't answered the question actually. you have x = 750, what's x? you were asked for two quantities and you only have one
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  3. #3
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    So
    750 kg of the first mixture, and
    250 kg of the second mixture, right?
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by nathan02079 View Post
    So
    750 kg of the first mixture, and
    250 kg of the second mixture, right?
    yes, but mixture means both, you should say 750 kg of the 55 cent/kg candy and 250 kg of the 75 cent/kg candy, or something like that
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  5. #5
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    Oh I see...thanks =)
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