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Math Help - prove using simultaneous equation?

  1. #1
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    prove using simultaneous equation?

    Having trouble with a prove, I'm not sure where to put this question.

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  2. #2
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    Re: prove using simultaneous equation?

    y = b/2x
    Substitute it in the first equation and simplify. Then solve the quadratics to get x^2.
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  3. #3
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    Re: prove using simultaneous equation?

    Quote Originally Posted by sa-ri-ga-ma View Post
    y = b/2x
    Substitute it in the first equation and simplify. Then solve the quadratics to get x^2.
    hi, thanks. I got that part, I'm just not sure how to simplify it.
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  4. #4
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    Re: prove using simultaneous equation?

    x^2 - (b / (2x))^2 - a = 0

    4x^4 - 4ax^2 - b^2 = 0

    Let u = x^2

    4u^2 - 4au - b^2 = 0

    Can you finish it?
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  5. #5
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    Re: prove using simultaneous equation?

    Quote Originally Posted by Wilmer View Post
    x^2 - (b / (2x))^2 - a = 0

    4x^4 - 4ax^2 - b^2 = 0

    Let u = x^2

    4u^2 - 4au - b^2 = 0

    Can you finish it?
    thanks, I think I still am having a bit of trouble with it. Do I have to complete the square or?
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  6. #6
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    Re: prove using simultaneous equation?

    Quote Originally Posted by chessweicong View Post
    thanks, I think I still am having a bit of trouble with it. Do I have to complete the square or?
    or use the quadratic formula.
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  7. #7
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    Re: prove using simultaneous equation?

    Quote Originally Posted by a tutor View Post
    or use the quadratic formula.
    ah, ok. thank you very much
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