$\displaystyle \frac{1}{\sqrt{2+x}-\sqrt{x}} + \frac{1}{\sqrt{2-x}+\sqrt{x}} = \frac{\sqrt{2}}{x}$
Can anyone please help me in solving this equation...?
It doesn't look like it can be solved exactly...
solve[ 1/( Sqrt[2+x] - Sqrt[x]) + 1/( Sqrt[2-x] + Sqrt[x] ) = Sqrt[2]/x] - Wolfram|Alpha