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Math Help - Figuring out how all these equal N[3]?

  1. #1
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    Figuring out how all these equal N[3]?

    ''[3]'' = power of 3

    (n-2)[3]

    (n-2)[2]x6

    (n-2)[12]

    8

    Do you expand the brackets? and then what?
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  2. #2
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    Re: Figuring out how all these equal N[3]?

    Quote Originally Posted by imalouski View Post
    ''[3]'' = power of 3

    (n-2)[3]

    (n-2)[2]x6

    (n-2)[12]

    8
    Pray tell what any of the above means!
    It makes no sense.
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  3. #3
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    Re: Figuring out how all these equal N[3]?

    Sorry, but that's what my teacher told us to write down and calculate how they equal N[3] - I'm as confused as you then haha
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  4. #4
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    Re: Figuring out how all these equal N[3]?

    Quote Originally Posted by imalouski View Post
    Sorry, but that's what my teacher told us to write down and calculate how they equal N[3] - I'm as confused as you then haha
    In that only your teacher or someone else in your class can truly help you.
    Help from anyone is probability useless to you.
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  5. #5
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    Re: Figuring out how all these equal N[3]?

    Hello, imalouski!

    Figuring out how all these equal N^3.
    I think it means: Show that these are "somethng cubed".


    (n-2)^3
    This is the cube of (n-2)


    (n-2)^2x^6
    (n-2)x^6 \;=\;\big[(n-2)x^2\big]^3

    This is the cube of (n-2)x^2



    (n-2)^{12}
    (n-2)^{12} \;=\;\big[(n-2)^4\big]^3

    This is the cube of (n-2)^4



    8
    8 \;=\;2^3

    This is the cube of 2.

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  6. #6
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    Re: Figuring out how all these equal N[3]?

    Would it make any difference if i changed the question to, ''Calculate why it equals N[3]"?
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