# Math Help - stuck with a logarithm

1. ## stuck with a logarithm

Hi;
Solve for x: 4log(x - 6) = 11

so far I'm hare log(x - 6)^4 = 11 (not sure where to go from here).

Thanks.

2. ## Re: stuck with a logarithm

Apply the function inverse to log to both sides.

3. ## Re: stuck with a logarithm

Yeah I got it thanks.

4. ## Re: stuck with a logarithm

The inverse of $log_a(x)$ is $a^x$- that is if $y= log_a(x)$ then $x= a^y$. Your problem is a little ambiguous because you do not give a base for the logarithm. Normally, that would imply the "common logarithm", base 10. If that is the base here, then $(x- 6)^4= 10^{11}$. That is probably correct here but in higher level mathematics it is common to use "log" rather than "ln" to mean the natural logarithm. If that is the case, then $(x- 6)^4= e^{11}$.