I need help with a work problem consiting of area and perimeter. I understand that A=1/2bh and that P = 2W x 2L. I am confused though when you have two different area's and you are to find the area and perimeter. Please advise, thanks dtofte

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- October 9th 2007, 08:40 PMdtofteArea and Perimeter
I need help with a work problem consiting of area and perimeter. I understand that A=1/2bh and that P = 2W x 2L. I am confused though when you have two different area's and you are to find the area and perimeter. Please advise, thanks dtofte

- October 10th 2007, 01:22 AMticbol
If you will not show us how the two rectangles are connected to form an L-shaped room, then the perimeter of the room is hard to guess.

The area, at any arrangement of the two rectangles, remains the same,

Area = (8.5)(11) +(6.5)(7.5) = 93.5 +48.75 = 142.25 sq.ft. - October 10th 2007, 02:53 AMdtofteAttached L-shaped room
I tried making an L-shaped room with the equation editor as best as I could. I hope it helps. Thanks, for the help with getting the area on my question.

dtofte - October 10th 2007, 03:06 AMticbol