Hey there. I am having difficulties with the Quadratic formula,

I know what goes where in the cases, but its just solving from there.

like in this equasion.

2x^2-5x=0

I know how to get it into the quadratic formula

this is what I got.

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- October 9th 2007, 06:12 PMfacesonfilmThe Quadratic Formula.
Hey there. I am having difficulties with the Quadratic formula,

I know what goes where in the cases, but its just solving from there.

like in this equasion.

2x^2-5x=0

I know how to get it into the quadratic formula

this is what I got. - October 9th 2007, 06:13 PMJhevon
- October 9th 2007, 06:23 PMfacesonfilm
I know C is zero there.. but isnt it in the form of Ax^2 + Bx + C?

so then when you plug it into the quadratic formula, you dont input a C. - October 9th 2007, 06:38 PMJhevon
- October 9th 2007, 06:39 PMfacesonfilm
so would the c (which is zero) make the whole 4ac equal zero?

- October 9th 2007, 06:43 PMJhevon
- October 9th 2007, 06:44 PMfacesonfilm
Oh kay, I didnt even catch that. Wow.

that sure makes me feel like a genius.

thanks alot!! - October 9th 2007, 06:45 PMSnipedYou
I'm surprised no one has pointed out that B is negative meaning that it should be

Since the quadratic is:

Making it

or just - October 9th 2007, 06:47 PMJhevon
- October 9th 2007, 06:49 PMfacesonfilm
So because I have a negitive with a negitive, it becomes a positive,

even in this case? Correct? - October 9th 2007, 06:50 PMJhevon
- October 9th 2007, 06:52 PMfacesonfilm
okay, I wasn't 100 % on that because our teacher just gave us the formula today like 5 minutes before the bell so I was kinda foggy on that.

- October 10th 2007, 02:00 PMshuggyboi
why dont you just factorise "2x^2 -5x = 0"

to "x(2x-5) = 0"

then x would have the values:

x = 0 and 2x-5 = 0

2x = 5

x =5/2

:confused: - October 10th 2007, 02:04 PMJhevon