Thread: Unsure on a problem

1. Unsure on a problem

I'm doing some fraction division, and on one problem i got an answer which was abnormally higher than all the other answers, which i found a little odd..so i want to get this checked and see if i did it right. the answers im comparing it to are correct, i checked in back of book(only has odd numbered problem answers)
49x/3.5

49x • 7
over1• over2

simplified..
171.5

er, the fractions came out kinda weird, but..the data is correct, the only problem is reading it

2. Originally Posted by Nightfire
I'm doing some fraction division, and on one problem i got an answer which was abnormally higher than all the other answers, which i found a little odd..so i want to get this checked and see if i did it right. the answers im comparing it to are correct, i checked in back of book(only has odd numbered problem answers)
1
49x/3 and -
2
49x 7 343x
--- • - = -----
1 2 2
simplified..
1
171 ---
2

er, the fractions came out kinda weird, but..the data is correct, the only problem is reading it
just type the fractions like this...(numerator)/(denominator)

so if you wanted to type something like $\displaystyle \frac {2x + 1}{5} + \frac {5x}{x + 1} = \frac {3x}4$ you would type:

(2x + 1)/5 + (5x)/(x + 1) = (3x)/4

now try again

3. okay, here goes:
49x divided by 3 1/2
(49x)/1 • 7/2
(343x)/2
simplified...
171 1/2

4. Originally Posted by Nightfire
okay, here goes:
49x divided by 3 1/2
(49x)/1 • 7/2
(343x)/2
simplified...
171 1/2
you did not follow my instructions

anyway, you are wrong. to divide by a fraction, you multiply by its reciprocal, so you should have $\displaystyle 49x \times \frac 27$

how did you end up with numbers at the end? where did the x go?

5. Ah, i see, i forgot to flip the 7/2 when i made it improper, and i forgot to put the x in the end on the post..didnt on the problem
thanks, i'll rework it