# Unsure on a problem

• Oct 9th 2007, 04:29 PM
Nightfire
Unsure on a problem
I'm doing some fraction division, and on one problem i got an answer which was abnormally higher than all the other answers, which i found a little odd..so i want to get this checked and see if i did it right. the answers im comparing it to are correct, i checked in back of book(only has odd numbered problem answers)
49x/3.5

49x • 7
over1• over2

simplified..
171.5

er, the fractions came out kinda weird, but..the data is correct, the only problem is reading it :o
• Oct 9th 2007, 04:31 PM
Jhevon
Quote:

Originally Posted by Nightfire
I'm doing some fraction division, and on one problem i got an answer which was abnormally higher than all the other answers, which i found a little odd..so i want to get this checked and see if i did it right. the answers im comparing it to are correct, i checked in back of book(only has odd numbered problem answers)
1
49x/3 and -
2
49x 7 343x
--- • - = -----
1 2 2
simplified..
1
171 ---
2

er, the fractions came out kinda weird, but..the data is correct, the only problem is reading it :o

just type the fractions like this...(numerator)/(denominator)

so if you wanted to type something like $\frac {2x + 1}{5} + \frac {5x}{x + 1} = \frac {3x}4$ you would type:

(2x + 1)/5 + (5x)/(x + 1) = (3x)/4

now try again
• Oct 9th 2007, 04:40 PM
Nightfire
okay, here goes:
49x divided by 3 1/2
(49x)/1 • 7/2
(343x)/2
simplified...
171 1/2
• Oct 9th 2007, 04:45 PM
Jhevon
Quote:

Originally Posted by Nightfire
okay, here goes:
49x divided by 3 1/2
(49x)/1 • 7/2
(343x)/2
simplified...
171 1/2

you did not follow my instructions

anyway, you are wrong. to divide by a fraction, you multiply by its reciprocal, so you should have $49x \times \frac 27$

how did you end up with numbers at the end? where did the x go?
• Oct 9th 2007, 04:48 PM
Nightfire
Ah, i see, i forgot to flip the 7/2 when i made it improper, and i forgot to put the x in the end on the post..didnt on the problem
thanks, i'll rework it