Hello I am new to this site, and I have to learn LaTex so please bare with me. Prove that if x,y >= 0, then . Thanks in advance.
Last edited by brucewayne; Aug 30th 2012 at 07:41 AM.
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The side condition should be x, y ≥ 1. Show that $\displaystyle y\sqrt{x-1}\le xy/2$ and $\displaystyle x\sqrt{y-1}\le xy/2$.
My sincerest apologies, the If statement should read x, y >= 1.
My apologies for being unprofessional and not employing LaTex. I am in the process of trying to figure LaTex out. At any rate, y*sqrt(x-1) + x*sqrt(y-1) < = (less than or equal) xy.
So, did the hint in post #2 help?
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