I got to the part where you have to divide (-25/2)/(5^3) and i'm stuck!

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- Aug 29th 2012, 04:14 PMEJdive43How would you solve this -(-3)^2-7(1/2)/5^3?
I got to the part where you have to divide (-25/2)/(5^3) and i'm stuck!

- Aug 29th 2012, 09:40 PMProve ItRe: How would you solve this -(-3)^2-7(1/2)/5^3?
$\displaystyle \displaystyle \begin{align*} \frac{-\frac{25}{2}}{5^3} &= -\frac{25}{2} \div 5^3 \\ &= -\frac{25}{2} \times \frac{1}{5^3} \\ &= -\frac{25}{2 \cdot 5^3} \\ &= -\frac{5^2}{2 \cdot 5^3} \\ &= -\frac{1}{2 \cdot 5} \\ &= -\frac{1}{10} \end{align*}$

- Aug 30th 2012, 12:12 PMEJdive43Re: How would you solve this -(-3)^2-7(1/2)/5^3?
Oh, I flipped the numoator. So you only take the receptacle of the demoninator?

- Aug 30th 2012, 03:58 PMWilmerRe: How would you solve this -(-3)^2-7(1/2)/5^3?
(a / x) / (b / y) = (a / x) * (y / b)

- Aug 30th 2012, 07:33 PMProve ItRe: How would you solve this -(-3)^2-7(1/2)/5^3?