Show That$\displaystyle \sqrt{8+2\sqrt{15}} $ in $\displaystyle (\sqrt{a}+\sqrt{b})$ this way.
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Originally Posted by srirahulan Show That$\displaystyle \sqrt{8+2\sqrt{15}} $ in $\displaystyle (\sqrt{a}+\sqrt{b})$ this way. Try to solve $\displaystyle 8+2\sqrt{15}=(\sqrt{a}+\sqrt{b})^2$ (i.e., find one simple solution). P.S. Why do you call "algebra," "algeb"? I've seen this word a number of times on this forum.
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