2e^2.1

that's two e to the power of 2.1

does this equal 16.33 (2dp) ?

Results 1 to 9 of 9

- Aug 28th 2012, 03:07 AM #1

- Joined
- Aug 2012
- From
- Manchester
- Posts
- 15

- Aug 28th 2012, 03:13 AM #2

- Aug 28th 2012, 03:59 AM #3

- Joined
- Oct 2009
- Posts
- 5,575
- Thanks
- 790

- Aug 28th 2012, 04:03 AM #4

- Joined
- Aug 2012
- From
- Manchester
- Posts
- 15

- Aug 28th 2012, 10:06 AM #5

- Joined
- Apr 2005
- Posts
- 18,950
- Thanks
- 2738

- Aug 28th 2012, 09:30 PM #6

- Joined
- Jul 2010
- From
- Vancouver
- Posts
- 432
- Thanks
- 17

## Re: 2e^2.1

Here's another perfectly fine way of doing this. You know how to take integer powers and suppose you have handy, to good precision. What can we do then? We have

Now you can use the Taylor series for that last exponential

If you have to several decimal places in precision, then you can get away with using less terms in this series. It's not a big save but it's kind of neat.

- Aug 29th 2012, 02:54 AM #7

- Joined
- Dec 2007
- From
- Ottawa, Canada
- Posts
- 3,184
- Thanks
- 80

- Aug 31st 2012, 05:55 AM #8

- Joined
- Jun 2012
- From
- UK
- Posts
- 5

- Aug 31st 2012, 06:02 AM #9

- Joined
- Oct 2009
- Posts
- 5,575
- Thanks
- 790