that's two e to the power of 2.1
does this equal 16.33 (2dp) ?
Here's another perfectly fine way of doing this. You know how to take integer powers and suppose you have handy, to good precision. What can we do then? We have
Now you can use the Taylor series for that last exponential
If you have to several decimal places in precision, then you can get away with using less terms in this series. It's not a big save but it's kind of neat.