Here I have a proof,can anybody explain how to proof it? $\displaystyle \frac{1}{1+x^{a-b}+x^{a-c}}+\frac{1}{1+x^{b-c}+x^{b-a}}+\frac{1}{1+x^{c-a}+x^{c-b}}=1$
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Originally Posted by srirahulan Here I have a proof,can anybody explain how to proof it? $\displaystyle \frac{1}{1+x^{a-b}+x^{a-c}}+\frac{1}{1+x^{b-c}+x^{b-a}}+\frac{1}{1+x^{c-a}+x^{c-b}}=1$ Have you considered trying to get a common denominator?
Originally Posted by srirahulan Here I have a proof,can anybody explain how to proof it? $\displaystyle \frac{1}{1+x^{a-b}+x^{a-c}}+\frac{1}{1+x^{b-c}+x^{b-a}}+\frac{1}{1+x^{c-a}+x^{c-b}}=1$ Take note that $\displaystyle \frac{1}{1+x^{a-b}+x^{a-c}}=\frac{x^{b+c}}{x^{b+c}+x^{a+c}++x^{a+b}}$.
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