1) multiply both sides by 2a
so you get so the 2a's cancel each other
add 4ac to both sides
in LHS take (a) as common factor
divid both sides by the term (2x+4c)
please help me with these algebra problems! thank you!
1.) solveb-4acx= ————2afor "a"
2.)simplify:
(5y)/(4xy^{2})•(3)/(5x)•(-3x^{2}y)/(3xy)
* the / means its a fraction.
1st one: easier if you use criss-cross multiplication (example: if a/b = c/d, then ad = bc):
2ax = b - 4ac : 2ax + 4ac = b : a(2x + 4c) = b : a = b / (2x + 4c)
2nd one: start by cancelling where possible; like 5y / (4xy^2) = 5 / (4xy)