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Math Help - Perpendicular equation help

  1. #1
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    Post Perpendicular equation help

    Find p such that the lines whose equations are 3px + 8y = 5 and 6y - 4px = -1 are perpendicular.

    The answer should be p = 2, -2

    But I don't understand how to obtain that.
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  2. #2
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    Re: Perpendicular equation help

    Right the equations in y=mx+b form. In the first equation you'll have the slope m_1=\frac{-3p}{8} and in the second m_2=\frac{4p}{6}=\frac{2p}{3}. Use what you know about the relationship between the slopes of perpendicular lines to solve for p.
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  3. #3
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    Re: Perpendicular equation help

    Quote Originally Posted by adkinsjr View Post
    Right the equations in y=mx+b form. In the first equation you'll have the slope m_1=\frac{-3p}{8} and in the second m_2=\frac{4p}{6}=\frac{2p}{3}. Use what you know about the relationship between the slopes of perpendicular lines to solve for p.
    Thank you For some reason I kept on getting 4, but then I realized I accidentally eliminated the p squared part. Thanks again!!
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