Find p such that the lines whose equations are 3px + 8y = 5 and 6y - 4px = -1 are perpendicular.

The answer should be p = 2, -2

But I don't understand how to obtain that.

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- Aug 18th 2012, 09:39 AMsnickerdoodle27Perpendicular equation help
Find p such that the lines whose equations are 3px + 8y = 5 and 6y - 4px = -1 are perpendicular.

The answer should be p = 2, -2

But I don't understand how to obtain that. - Aug 18th 2012, 10:35 AMadkinsjrRe: Perpendicular equation help
Right the equations in y=mx+b form. In the first equation you'll have the slope $\displaystyle m_1=\frac{-3p}{8}$ and in the second $\displaystyle m_2=\frac{4p}{6}=\frac{2p}{3}$. Use what you know about the relationship between the slopes of perpendicular lines to solve for p.

- Aug 18th 2012, 10:53 AMsnickerdoodle27Re: Perpendicular equation help