If 6 time j is 1 more than the square of k, where k is an integer, what is the smallest possible value of j?

How can I show that it is indeed 1/6 ?

(Converting into symbols: 6j=k^2 + 1 but I'm stuck..)

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- Aug 17th 2012, 10:26 PMdonnagirlWord problem
If 6 time j is 1 more than the square of k, where k is an integer, what is the smallest possible value of j?

How can I show that it is indeed 1/6 ?

(Converting into symbols: 6j=k^2 + 1 but I'm stuck..) - Aug 17th 2012, 10:41 PMMaxJasperRe: Word problem
You should prove that there exist no integer k such that (1+k^2) be divisible by 2 & 3 at the same time. 1+k^2 either is odd or even hence in each case is not divisible either by 2 or 3

- Aug 18th 2012, 05:04 AMWilmerRe: Word problem