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Math Help - Solving a, what am I doing wrong.

  1. #1
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    Solving a, what am I doing wrong.

    Can someone please tell me where am I going wrong?
    Solve a
    b=a^3/\sqrt[3]{a}
    b= a^3/1/a^3
    b= a^3*1/a^3/1/a^3*1/a^3
    b= a^3/1*1/a^3
    b=1

    This is not right ... don't know where to start or where to go with it.

    c = b^-2/\sqrt[3]{a}
    c = 1/b^2/*c^1/2
    c = 1/b^2*b^2/1*a^1/2
    c = b^2*a^1/2
    c = b^2*a^1/2/b^2
    c/b^2 = a^1/2
    a^1/2 = c/b^2

    I am going way off the tracks here, please correct me.

    Thanks in advance - Roux
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  2. #2
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    Re: Solving a, what am I doing wrong.

    b = \frac{a^3}{\sqrt[3]{a}}

    b = \frac{a^3}{a^{1/3}}

    b = a^{8/3}

    b^{3/8} = a



    c = \frac{b^{-2}}{\sqrt[3]{a}}

    \sqrt[3]{a} = \frac{b^{-2}}{c}

    \sqrt[3]{a} = \frac{1}{b^2c}

    a = \frac{1}{b^6c^3}
    Thanks from HallsofIvy and Rpuxster
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  3. #3
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    Re: Solving a, what am I doing wrong.

    Thank you, I can see where I went wrong ...
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  4. #4
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    Re: Solving a, what am I doing wrong.

    HallsofIvy, plase tell me what happened in problem one, in step 3 - thank you.
    b = a^{3/8}
    Last edited by Rpuxster; August 15th 2012 at 12:37 PM.
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  5. #5
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    Re: Solving a, what am I doing wrong.

    ... Ok i have it 3*3-1
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