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Math Help - Why can't I divide 2 to the other side in y+1=2square root/y+1?

  1. #1
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    Why can't I divide 2 to the other side in y+1=2square root/y+1?

    Why can't I divide 2 to the other side in y+1=2square root/y+1? I would like to get rid of the square root in y+1 by squaring it, but my answer sheet say I can't divide the 2 out but I just have to square it with the SR/y+1 to get y.
    Original problem: sr/2y+3-sr/y+1=1
    I don't know where to find the symbol for square root so I say "sr/"
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  2. #2
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    Re: Why can't I divide 2 to the other side in y+1=2square root/y+1?

    To make square roots in LaTeX, click "Go Advanced" then click on the TeX tags (which will look like a sigma \Sigma). The square root of y+1 is denoted by \sqrt{y+1}, which yields \sqrt{y+1}.

    As of right now, your question's too unclear...it seems like you are saying y+1 = 2\sqrt{y+1} but I don't want to guess.
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  3. #3
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    Re: Why can't I divide 2 to the other side in y+1=2square root/y+1?

    You guess correctly! Why can't I divide the 2?
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    Re: Why can't I divide 2 to the other side in y+1=2square root/y+1?

    Quote Originally Posted by EJdive43 View Post
    You guess correctly! Why can't I divide the 2?
    You could divide both sides by 2 to obtain \frac{y+1}{2} = \sqrt{y+1}, but you don't really have to.
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  5. #5
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    Re: Why can't I divide 2 to the other side in y+1=2square root/y+1?

    Ok, how would you solve sr/2y+3-sr/ y+1= 1? Please write it in steps.
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  6. #6
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    Re: Why can't I divide 2 to the other side in y+1=2square root/y+1?

    You should try to use the typesetting here. Or at least use sqrt(2y+3) - sqrt(y+1) = 1.

    I think you're on the right track, I did it myself by rearranging and squaring both sides twice, obtaining

    y+1 = 2 \sqrt{y+1}

    From here should be easy. Square both sides (again) to get

    (y+1)^2 = 4(y+1)

    (y+1)^2 - 4(y+1) = 0. Here, note that the LHS factors to

    (y+1)((y+1) - 4) = 0 (if you don't see this immediately, you could perhaps let u = y+1 and factor).

    Solving, we get y = -1 and y = 3. Both solutions work.
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