Please help!! solve for x

**etran3358** · August 12th 2012, 11:25 AM

$1/3x^2 - 5/6x =1$

$x^3 -26x ^3 / ^2 =27$

$2x^2(2x-1) ^1/ ^3 =4x(2x-1) ^4 / ^3$

$15/ 2^x -1 = 7$ this reads as 15 ALL OVER 2^x -1

**HallsofIvy** · August 12th 2012, 12:33 PM

Do you not have parentheses keys on your keyboard? You posted similar questions (in several cases exactly same equations) yesterday and were told why it was impossible to be certain what you meant.

**etran3358** · August 12th 2012, 12:42 PM

$(1/3)x^2-(5/6)x=1$

$(x)^3-(26)(x ^ 3 / ^ 2) = 27$

$(2x^2)(2x-1)(^1/^3) = (4x)(2x-1) (^4/ ^3)$

$(15) / (2^x - 1) =7$

i hopw this is better ... sorry about that

**etran3358** · August 12th 2012, 02:08 PM

AP Calculus Ab 2011 Summer Work Part 1

if you're having trouble still reading it please open this document and look at #'s 2, 10,11,15,37, and 40 ( the same exact problems i need help)

any help on this problems would be appreciated!!

**skeeter** · August 12th 2012, 03:17 PM

looks like a graded assignment ... thread closed.

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