$1/3x^2 - 5/6x =1$

$x^3 -26x ^3 / ^2 =27$

$2x^2(2x-1) ^1/ ^3 =4x(2x-1) ^4 / ^3$

$15/ 2^x -1 = 7$ this reads as 15 ALL OVER 2^x -1

Do you not have parentheses keys on your keyboard? You posted similar questions (in several cases exactly same equations) yesterday and were told why it was impossible to be certain what you meant.

$(1/3)x^2-(5/6)x=1$

$(x)^3-(26)(x ^ 3 / ^ 2) = 27$

$(2x^2)(2x-1)(^1/^3) = (4x)(2x-1) (^4/ ^3)$

$(15) / (2^x - 1) =7$

i hopw this is better ... sorry about that

AP Calculus Ab 2011 Summer Work Part 1

if you're having trouble still reading it please open this document and look at #'s 2, 10,11,15,37, and 40 ( the same exact problems i need help)

any help on this problems would be appreciated!!