Sorry, I'm not good with notations, if you can't understand this: the m root of (16^2m + 64^m) /(8^m + 32^m) Here's an image of the equation: The answer, according to the book, is 8, but, unfortunately, it doesn't show the solution. Can you show me why it's 8 please? Thanks a lot!
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I'll get you started, $\displaystyle \frac{16^{2m}+64^m}{8^m+32^m}$ $\displaystyle =\frac{(2^4)^{2m}+(2^6)^m}{(2^3)^m+(2^5)^m}$ $\displaystyle =\frac{2^{8m}+2^{6m}}{2^{3m}+2^{5m}}$ Now factorise..
Originally Posted by a tutor I'll get you started, $\displaystyle \frac{16^{2m}+64^m}{8^m+32^m}$ $\displaystyle =\frac{(2^4)^{2m}+(2^6)^m}{(2^3)^m+(2^5)^m}$ $\displaystyle =\frac{2^{8m}+2^{6m}}{2^{3m}+2^{5m}}$ Now factorise.. Actually, that's where I get stuck. I can't get past that point, but good to know I was on the right track
Last edited by viccal; Aug 12th 2012 at 01:16 AM.
$\displaystyle =\frac{2^{8m}+2^{6m}}{2^{3m}+2^{5m}}$ $\displaystyle =\frac{2^{6m}(2^{2m}+1)}{2^{3m}(2^{2m}+1)}=2^{3m}$
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