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Math Help - natural log help

  1. #1
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    natural log help

    I'm using this formula to analyze data, and don't quite understand this step... I just can't quite remember if ln works like this, but if somebody can just either confirm that this is correct, or if not, that would be great

    the original equation is ln(B) = c +α ln(d)

    I have c,
    α, and d, and am trying to solve for B

    so, can I solve with B = c + d^
    α

    thanks!
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  2. #2
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    Re: natural log help

    Quote Originally Posted by forgetful View Post
    the original equation is ln(B) = c +α ln(d)
    I have c,
    α, and d, and am trying to solve for B
    Well the answer is B=d^a\cdot e^c.
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  3. #3
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    Re: natural log help

    Thanks Plato, had a feeling there was something missing
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