Thread: The Hulk

The Hulk loves eating candy. He bought 50 pieces on Monday and marks 50% red, 10% yellow, 38% orange, and 2% green, his favorite color. Then, on Tuesday, he eats 5 and splits the rest among himself and 4 other heroes. On Wednesday, each of the super humans eat 4 pieces. On Thursday, an alien abducts 40 percent of the remaining amount of candy. On Friday, Dr. Wonka steals 2 pieces from each child and throws them into a fire. On Saturday, deciding that the candy had gotten into too much trouble, The Hulk takes his candies back. After realizing that one of the candies was broken, he Hulk smashes all his candy, except for one that escapes the attack. What is the probability that the candy that survives is (1)red, (2) yellow, (3) orange, or (4) green? Show all your work.

well i know there are 4 "unbroken" candies when hulk smashes them. i just completely forgot how to figure out the probabilities.

you should just give me the answer and show your work

50% red, 10% yellow, 38% orange, and 2% green?

I don't know the answer. Please explain to me how you got your answer.

Originally Posted by ReginaldCuthbert

50% red, 10% yellow, 38% orange, and 2% green?

The OP means that of the 50 pieces of candy, 50% are red, 10% are yellow, 38% are orange and 2% are green.

That's a "purposefully" worded problem to make it appear harder than it is.
It's the same as: a bag contains 50 marbles: 25 red, 19 orange, 5 yellow and 1 green.
One marble is picked at random: what is the probability that it is (1)red, (2) yellow, (3) orange, or (4) green?
Answer: red: 25/50, orange: 19/50, yellow: 5/50, green: 1/50.

Yours is same thing, achieved by removing 49, the probability applicable to the 1 remaining.
In other words: a silly probability problem!

no that was my nervous guess answer... i got it right!