Basicaly, I need help on this sequence, as my homework is due in tomorrow. One question on sequences is:
1
3
11
67
I'm supposed to find out what comes next. Can anyone help? Even if you tell me how you got the answer, that would be a great help
Basicaly, I need help on this sequence, as my homework is due in tomorrow. One question on sequences is:
1
3
11
67
I'm supposed to find out what comes next. Can anyone help? Even if you tell me how you got the answer, that would be a great help
You made no mistake, one can chose the next term to have an arbitary
value and find a polynomial that will take all the given values and our arbitary
next value.
Your cubic does give the first four terms, and so is as valid a rule for the
next term as any other, and I suspect it involves no more arbitary constants
than does Soroban's
RonL
HellO!
RonL and Dan are, of course, absolutely correct.
A sequence of numbers is meaningless unless there is a stipulation,
. . a promise that that the sequence "continues in a similar manner",
. . that there is indeed a "reasonable" pattern to the terms.
I've posted the following before, but I enjoy showing it off.
Find the next term of the sequence: .
Answer: 8
Justification
I was using this function: .
"That's unfair!" you say?
Okay, here's a better explanation . . .
The sequence: . is the sequence of natural numbers
. . whose English names contain the letter "e".