1. ## Circle Graph Help

Zoo Admission Fee Usage (per dollar)

Grounds maintenance- $0.55 Animal care-$0.20

Building fund- $0.15 Salaries-$0.10

The question is:

"To make a circle graph of the data in the table, how many degrees would represent animal care?"

How do I do this?

2. Originally Posted by Mac Addict
Zoo Admission Fee Usage (per dollar)

Grounds maintenance- $0.55 Animal care-$0.20

Building fund- $0.15 Salaries-$0.10

The question is:

"To make a circle graph of the data in the table, how many degrees would represent animal care?"

How do I do this?
i suppose by circle graph you mean pie chart.

think of the cents as percentages of the dollar. so ground maintenance takes up 55% of the dollar, etc. now, we want to divide a circle based on these percentages. so a slice of the pie with 55% of the degrees at the center will represent the ground maintenance and so on for the rest. how do we find the degrees? well, we remember that "percent" means "out of 100" and "of" means multiply and a circle has 360 degrees. so,

for ground maintenance, we have:

$\displaystyle \frac {55}{100} \times 360 = 198^{\circ}$

so the slice with $\displaystyle 198^{\circ}$ corresponds to the ground maintenance. do similar calculations for the others, and then draw your pie chart. (oh, you just have to do "animal care" well, that's even better)

Organize the data like this:

$\displaystyle \begin{array}{ccccccc} \text{Usage} &|& \text{Amount} & | & & \text{Fraction} & \\ \hline \text{Maintenance} & | & \$0.55 & | & \frac{55}{100} & = & \frac{11}{20} \\
\text{Animal care} &|& \$0.20 &|& \frac{20}{100} & = & \frac{1}{5} \\ \text{Bldg. fund} &|& \$0.15 &|& \frac{15}{100} & = & \frac{3}{20} \\
\text{Salaries} &|& \$0.10 &|& \frac{10}{100} & = & \frac{1}{10}\\ \hline\end{array}$

To make a circle graph of the data in the table,
how many degrees would represent animal care?"
Since Animal Care comprises $\displaystyle \frac{1}{5}$ of the expenses, it takes up $\displaystyle \frac{1}{5}$ of the circle.
. . Therefore: .$\displaystyle \frac{1}{5} \times 360^o \;=\;72^o$

Similarly, Maintenance would have: .$\displaystyle \frac{11}{20} \times 360^o \:=\:198^o$

Get the idea?