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Math Help - Need help with this math question please help me?

  1. #1
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    Need help with this math question please help me?

    A lawn is 30m by 35m. The fertilizer for the lawn is applied at 5 Ibs per 750 square feet and comes in 50 Ibs bags. How many bags are need?

    note: If you know the answers can you please explain it to me in simple terms? Don't put anything complicated. Thank you.
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  2. #2
    Senior Member DivideBy0's Avatar
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    Are you sure the scaling is correct? It's just that it's odd to have metres and feet (Imperial System and SI) in the same question.

    Ok, assuming you mean 30 feet by 35 feet,

    Then the area of the lawn is 30 \times 35=1050 square feet

    Now, since 5 pounds covers 750 square feet, 50 pounds (1 bag) will cover 7500 square feet.

    Now we can use ratios to determine how many bags we need. Let x be the number of bags we need.
    As you can see, the ratios of the areas of the lawn is 1050:7500
    and the ratio of the bags needed is x:1

    Note that 1050:7500=x:1

    That is,

    \frac{1050}{7500}=\frac{x}{1}

    Now simply solve for x:

    x=\frac{1050}{7500}=\frac{105}{750}=\frac{21}{150}  =\frac{7}{50} of a bag.
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  3. #3
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    whats with the : ?
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  4. #4
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    it's not 30feet by 35feet. It's m it says in my textbook.
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  5. #5
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    You have to convert the feet to meters or viceversa and everything would be alot more simple.. no? Just find the conversion rate and then it's just simple math
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  6. #6
    is up to his old tricks again! Jhevon's Avatar
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    google works as a calculator and unit converter. According to google:

    1 meter = 3.2808399 feet
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  7. #7
    Senior Member DivideBy0's Avatar
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    Quote Originally Posted by billR2D2 View Post
    whats with the : ?
    Sorry about the scaling issues I had,

    a:b=\frac{a}{b}, usually only used when comparing objects.

    Ratios

    Replace 1050m^2 with 1050* 3.280 839 895 feet squared and continue as I did.
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  8. #8
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    Logarithm

    Please shed some light on the following......

    If x and y are both positive and log_9 x = log_12 y = log_16 (x + y), find the value of x/y.
    Note: log_9 x should read log base 9 x
    Thanks.
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