Originally Posted by

**rcs** I just wonder why when i solved

|x+2|^2 < |x( x - 1)|^2

.

.

.( x +2 )^2 - ( x^2 - x) ^2 < 0

.( 2 + 2x - x^2) ( x^2+2) < 0

.- ( x^2 - 2x - 2) ( x^2 + 2) < 0

since it is < 0 then i have to reject the ( x^2 + 2)

. then i have left (x^2 - 2x - 2) > 0

. square root of (x - 1)^2 > square root of 3

. |x -1| > sq. root 3

then i finally have these roots x > 1 + sq. root of 3 or x > 1 - sq. root of 3

and my classmate said that the other has to be x < 1 - sq. root of 3... i wonder why it should reverse.

that is my problem...

i need guide here.

Thanks