# Math Help - Solving for x

1. ## Solving for x

$\ln{x+2}={(x-3)^2}$

I think I'm forgetting an algebraic concept in solving for x in this problem. I have gone as far as square rooting both sides to yield: $\sqrt{\ln{x+2}}={(x-3)}$

Is there anyway to detach the x from the natural log?

2. ## Re: Solving for x

Originally Posted by AZach
$\ln{x+2}={(x-3)^2}$

I think I'm forgetting an algebraic concept in solving for x in this problem. I have gone as far as square rooting both sides to yield: $\sqrt{\ln{x+2}}={(x-3)}$

Is there anyway to detach the x from the natural log?
You won't be able to solve this exactly. You'll have to use a numerical method like the bisection method.