Solving for x

**AZach** · August 1st 2012, 08:42 PM

$\ln{x+2}={(x-3)^2}$

I think I'm forgetting an algebraic concept in solving for x in this problem. I have gone as far as square rooting both sides to yield: $\sqrt{\ln{x+2}}={(x-3)}$

Is there anyway to detach the x from the natural log?

**Prove It** · August 1st 2012, 08:46 PM

Originally Posted by AZach

$\ln{x+2}={(x-3)^2}$

I think I'm forgetting an algebraic concept in solving for x in this problem. I have gone as far as square rooting both sides to yield: $\sqrt{\ln{x+2}}={(x-3)}$

Is there anyway to detach the x from the natural log?

You won't be able to solve this exactly. You'll have to use a numerical method like the bisection method.

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