# Solving for x

• August 1st 2012, 08:42 PM
AZach
Solving for x
$\ln{x+2}={(x-3)^2}$

I think I'm forgetting an algebraic concept in solving for x in this problem. I have gone as far as square rooting both sides to yield: $\sqrt{\ln{x+2}}={(x-3)}$

Is there anyway to detach the x from the natural log?
• August 1st 2012, 08:46 PM
Prove It
Re: Solving for x
Quote:

Originally Posted by AZach
$\ln{x+2}={(x-3)^2}$

I think I'm forgetting an algebraic concept in solving for x in this problem. I have gone as far as square rooting both sides to yield: $\sqrt{\ln{x+2}}={(x-3)}$

Is there anyway to detach the x from the natural log?

You won't be able to solve this exactly. You'll have to use a numerical method like the bisection method.