If q is 10% greater than p and r is 10% greater than y, qr is what percent greater than py?

I set up the following equations, Q=10/100(p)+p

R=10/100(y)+y

QR=x/100(py)+py

How do I solve them? I would appreciate any response.

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- July 27th 2012, 12:16 PMSewilliams13Percent Greater than Problem?
If q is 10% greater than p and r is 10% greater than y, qr is what percent greater than py?

I set up the following equations, Q=10/100(p)+p

R=10/100(y)+y

QR=x/100(py)+py

How do I solve them? I would appreciate any response. - July 27th 2012, 03:22 PMSorobanRe: Percent Greater than Problem?
Hello, Sewilliams13!

Quote:

I prefer simpler fractions.

Multiply [1] and [2]: .

. . . . . . . . . . . . . . . .

- July 27th 2012, 05:14 PMSewilliams13Re: Percent Greater than Problem?
In [1] & [2] why did you take a way the p and the y in the next equation

- July 27th 2012, 07:32 PMWilmerRe: Percent Greater than Problem?
They were not "taken away"; they were simply added together; like, 1 + 1/10 = 10/10 + 1/10 = 11/10

- July 30th 2012, 12:47 PMSewilliams13Re: Percent Greater than Problem?
-_-Ahh...Thank you so much!