So i'm having trouble with simultaneous equations, the equations are:
y^2 + x^2 = 150^2
3y + 2x = 180
Looks quite simple but i'm not sure where to get started mainly because of the '150^2'.
Please help.
you can isolate $\displaystyle y$ (or x) from the second equation, so that
$\displaystyle y=60-\frac{2x}{3}$
then substitute it to the first equation,
$\displaystyle \begin{align*}\left(60-\frac{2x}{3}\right)^2+x^2 &=150^2\\60^2-\frac{2\times 60\times 2x}{3}+\frac{4x^2}{9}+x^2&=150^2\\\frac{4x^2}{9}+x ^2-80x+(60-150)(60+150)&=0\\13x^2-720x+9\times (-90)\times 210&=0\\13x^2-720x-170100&=0 \end{align*}$
this is a quadric equation, hope you can solve it