Well, divide by 3 to start: x^2 + 2x - 1
Now explain your question!
If it was x^2 + 2x + 1, then that would factor to (x + 1)^2
As Wilmer said, you factor out the "3" in each term: . Other than that, it cannot be factored with integer coefficients. The fact is that [b]most[b] polynomials cannot be factored with integer coefficients.
(I keep saying "with integer coefficients" because we could say that . And now we can use the simple rule so that . Of course, to do that, I had to, effectively, solve the equation by 'completing the square' and, since a main application of factoring is to solve equations, we usually mean "with integer coeffcients". But, once again, most polynomial equations can't be factored that way.)
first you have to convert it into quadratic form of equation
i.e a x^2 + b x + c =0
then find D = b^2 - 4ac
if D>0 then factor of equation is possible
X1 = [ -b + sqrt(D) ] / 2a
X2 = [ -b - sqrt(D) ] / 2a
..... try it also helps you Quadratic Equation
I came across this formula, I heard this one is used when there is no easy way to factor. What is the story with this formula and how does it works?
I'm a programmer and I am liking La Text
Edit: My bad, I fixed the sign before 4ac.