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Math Help - Alg. 2, Quadratics

  1. #1
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    Alg. 2, Quadratics

    I am having trouble with two problems.

    1.

    Edit: figured it out

    2.

    3(x+7/3)^2 = 1

    I'm just lost on that one D:


    Thanks for any help you guys have for me
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by ajm490 View Post
    I am having trouble with two problems.

    1.

    (x-3/5)^2 = 4/5

    I turn it into x^2 -6/5X+9/25= 4/5 and then x^2 -6/5X-11/25 = 0.

    Then I get stuck trying to plug that into the quadratic formula.
    <br />
(x-3/5)^2 = 4/5<br />

    so:

    <br />
x-3/5 = \pm \sqrt{4/5}<br />

    hence:

    <br />
x = 3/5 \pm \sqrt{4/5}<br />

    No need for the quadratic formula

    RonL
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by ajm490 View Post
    2.

    3(x+7/3)^2 = 1
    do not delete your questions after they have been solved

    3(x + 7/3)^2 - 1 = 0

    \Rightarrow 3 \left( x^2 + \frac {14}3x + \frac {49}{9} \right) - 1 = 0

    can you take it from here?
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  4. #4
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    Yes, I think so. And I found the answer by myself actually, prior to him completing it, which is why I took it off.

    Thanks to both of you though.
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  5. #5
    Grand Panjandrum
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    Quote Originally Posted by ajm490 View Post
    I am having trouble with two problems.

    1.

    Edit: figured it out

    2.

    3(x+7/3)^2 = 1

    I'm just lost on that one D:


    Thanks for any help you guys have for me
    Same as other one:

    <br />
3(x+7/3)^2 = 1<br />

    so:

    <br />
(x+7/3)^2 = 1/3<br />

    then:

    <br />
x+7/3 = \pm \sqrt{1/3}<br />

    hence:

    <br />
x = -7/8 \pm \sqrt{1/3}<br />

    RonL
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  6. #6
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by CaptainBlack View Post
    Same as other one:

    <br />
3(x+7/3)^2 = 1<br />

    so:

    <br />
(x+7/3)^2 = 1/3<br />

    then:

    <br />
x+7/3 = \pm \sqrt{1/3}<br />

    hence:

    <br />
x = -7/8 \pm \sqrt{1/3}<br />

    RonL
    i was working too hard
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  7. #7
    Grand Panjandrum
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    Quote Originally Posted by Jhevon View Post
    i was working too hard
    I had thought of mntioning that, but then ..

    RonL
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