2/ (6+lxl) two over 6 plus absloute value of x i got 1/3 +2/lxl
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$\displaystyle \frac{2}{6+|x|} \neq \frac{1}{3}+\frac{2}{|x|}$ Substitute 2 into both sides to confirm. What are you trying to achieve with this problem, what did the question ask?
Just a try.... 2 1 2 _____ = ____ + ___ 6+|x| 3 |x| 2 3 ____ = ____ 6X 3X 3X > X
Last edited by skeeter; Jul 30th 2012 at 07:10 AM. Reason: deleted spam link
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