Thread: home work

2/ (6+lxl)

two over 6 plus absloute value of x

i got 1/3 +2/lxl

$\displaystyle \frac{2}{6+|x|} \neq \frac{1}{3}+\frac{2}{|x|}$

Substitute 2 into both sides to confirm.

What are you trying to achieve with this problem, what did the question ask?

Just a try....


2 1 2
_____ = ____ + ___
6+|x| 3 |x|

2 3
____ = ____
6X 3X

3X > X