How have you got ? I don't understand what you're trying to achieve.
I'll presume the denominator on the left side is
Wouldn't it be better to use the least common denominator?
Since , that is the least common denominator and we can just multiply numerator and denominator of the second fraction by x- 1:
That is still not "x+1".
"that is the least common denominator and we can just multiply numerator and denominator of the second fraction by x- 1:"
why did you only multiple the second fraction? can you even do that?
what i did was mutiple both fractions by (x+1)(x-1) THUS making 2x - x-1= x-1
i'm aware i originally said my answer was x+1. this has been revised to x-1
In this case we have as the first denominator, and as the second denominator. Can you see that you already have a factor of in your first denominator? So all you need to get the lowest common denominator is that extra factor of .
It is basically the same thing you learned in arithmetic: in order to add or subtract fractions, you need to get the same denominator.
If, for example, you want to add and you could get a common denominator by multiplying, both numerator and denominator of the first fraction by 6, and of the second fraction by 3: which reduces to .
But since 6= 2(3), we can get the "least common denominator" of 6 by multiplying numerator and denominator of the first fraction by 2: .