x^2-6xy+10y^2=4 find all the integer pairs of x and y which satisfiy the equation. Thanks!
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You can solve for x and then choose y values that give integer values of x.
Originally Posted by Telo x^2-6xy+10y^2=4 find all the integer pairs of x and y which satisfiy the equation. Thanks! , , the quadratic formula yields ... since x is an integer value, the value under the radical must be a positive, perfect square value ... finish it.
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