x^2-6xy+10y^2=4

find all the integer pairs of x and y which satisfiy the equation.

Thanks!

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- Jul 13th 2012, 10:37 AMTeloParametric Equation Problem
x^2-6xy+10y^2=4

find all the integer pairs of x and y which satisfiy the equation.

Thanks! - Jul 13th 2012, 12:00 PMa tutorRe: Parametric Equation Problem
You can solve for x and then choose y values that give integer values of x.

- Jul 13th 2012, 01:51 PMskeeterRe: Parametric Equation Problem
$\displaystyle x^2 - 6xy + 10y^2 - 4 = 0$

$\displaystyle a = 1$ , $\displaystyle b = -6y$ , $\displaystyle c = 10y^2 - 4$

the quadratic formula yields ...

$\displaystyle x = 3y \pm \sqrt{4 - y^2}$

since x is an integer value, the value under the radical must be a positive, perfect square value ... finish it.