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Math Help - Stuck on inverting a function

  1. #1
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    Stuck on inverting a function

    f(x)=0.5+\frac{5}{0.2x} ,x\neq0

    I'm having some difficulty on finding the inverse function for this problem.

    I follow the first method of switching the 'x' and 'y' variables and then subtracting the 0.5 from both sides, x-0.5=\frac{5}{0.2y}. Here's where my intuition breaks down. I know the objective is to solve for 'y'. Thus, multiply '0.2y' on both sides? 0.2y(x-0.5)=5.

    Should I divide by (x-0.5)? That would give me 0.2y=\frac{5}{x-0.5}

    And then divide 0.2 from both sides and I end up with y=\frac{1}{x-0.5}

    I've tried working some inputs and the function is definitely not the inverse function, so I know my math is wrong. If somebody could toss me a tip I would appreciate it.
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    Re: Stuck on inverting a function

    Quote Originally Posted by AZach View Post
    f(x)=0.5+\frac{5}{0.2x} ,x\neq0

    I'm having some difficulty on finding the inverse function for this problem.

    I follow the first method of switching the 'x' and 'y' variables and then subtracting the 0.5 from both sides, x-0.5=\frac{5}{0.2y}. Here's where my intuition breaks down. I know the objective is to solve for 'y'. Thus, multiply '0.2y' on both sides? 0.2y(x-0.5)=5.

    Should I divide by (x-0.5)? That would give me 0.2y=\frac{5}{x-0.5}

    And then divide 0.2 from both sides and I end up with y=\frac{1}{x-0.5}

    5 divided by 0.2 is 25, not 1
    ...
    Thanks from AZach
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