# Math Help - Equation with negative variable exponent giving me trouble

1. ## Equation with negative variable exponent giving me trouble

How would this be worked out if there was a negative exponent of x? Lets say:

3x - 4 * 3-x > 0

It seems as if I put those into logs, it would turn into

x log 3 + (-x)log 3 > log 4

Would that be the correct way of doing it? Because that looks like the two x log 3 groups should cancel each other out. Even if I use x log 1/3, wouldnt that then be x log (3)(1/3) and just become log 1, which would be log 0?

2. ## Re: Equation with negative variable exponent giving me trouble

Originally Posted by Latsabb
How would this be worked out if there was a negative exponent of x? Lets say:

3x - 4 * 3-x > 0
Multiply by $3^{-1}$ and you get $9^x-4>0$.