How would this be worked out if there was a negative exponent of x? Lets say:

3^{x}- 4 * 3^{-x}> 0

It seems as if I put those into logs, it would turn into

x log 3 + (-x)log 3 > log 4

Would that be the correct way of doing it? Because that looks like the two x log 3 groups should cancel each other out. Even if I use x log 1/3, wouldnt that then be x log (3)(1/3) and just become log 1, which would be log 0?