http://latex.codecogs.com/gif.latex?...=\frac{x+1}{x}

Where to go from here?

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- July 1st 2012, 10:27 PMRemrielExponential Equation
http://latex.codecogs.com/gif.latex?...=\frac{x+1}{x}

Where to go from here? - July 1st 2012, 10:42 PMProve ItRe: Exponential Equation
- July 1st 2012, 10:52 PMearbothRe: Exponential Equation
- July 2nd 2012, 12:48 AMbiffboyRe: Exponential Equation
Go back to (x)log5=(x+1)log4

So (x)log5=(x)log4+log4

x(log5-log4)=log4

x=(log4)/(log5-log4} - July 2nd 2012, 06:03 AMRemrielRe: Exponential Equation
What about this one? I can't find a way to separate:http://latex.codecogs.com/gif.latex?...ac{log3}{log2}

- July 2nd 2012, 06:05 AMProve ItRe: Exponential Equation
- July 2nd 2012, 04:03 PMRemrielRe: Exponential Equation
Is this correct?

http://latex.codecogs.com/gif.latex?...{7} \right ]+2 - July 2nd 2012, 04:26 PMskeeterRe: Exponential Equation

cross multiply ...

distribute both sides ...

get all x terms on the same side ...

factor out the x ...

solve for x ...

- July 2nd 2012, 10:00 PMProve ItRe: Exponential Equation