Suppose I have to solve for y:

So I know that (x - 1) will always be 0 or a negative, therefore I must take the negative square root of (x - 1):

Am I to understand that this is the same as:

Or how does this work?

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- Jun 30th 2012, 05:59 AMdaigoManipulation of negative square root of a negative term/#
Suppose I have to solve for y:

So I know that (x - 1) will always be 0 or a negative, therefore I must take the negative square root of (x - 1):

Am I to understand that this is the same as:

Or how does this work? - Jun 30th 2012, 06:19 AMPlatoRe: Manipulation of negative square root of a negative term/#
- Jun 30th 2012, 06:21 AMSorobanRe: Manipulation of negative square root of a negative term/#
Hello, daigo!

Quote:

From [1]: .

Substitute into [2]: .

. . Therefore: .

- Jun 30th 2012, 06:32 AMdaigoRe: Manipulation of negative square root of a negative term/#
I don't really want to focus on solving the problem, I just need some insight on the negative square root operation.

I'm trying to understand the way it was done here:

Is this correct or incorrect? - Jun 30th 2012, 10:33 AMWilmerRe: Manipulation of negative square root of a negative term/#
Incorrect.

- Jun 30th 2012, 04:06 PMthevinhRe: Manipulation of negative square root of a negative term/#
- Jun 30th 2012, 05:10 PMPlatoRe: Manipulation of negative square root of a negative teronfusiom/#
- Jun 30th 2012, 11:57 PMbiffboyRe: Manipulation of negative square root of a negative term/#
Is there anything wrong with this.

(x-1)= + or -root y So rooty=(x-1) or (1-x) For example if x=-2 y=9 and root y =+3 or -3 - Jul 1st 2012, 01:35 AMBobPRe: Manipulation of negative square root of a negative term/#
Can I join in ? What's wrong with this ?

so either or

If then so concentrate on the first case.

If then ( is positive), but we know that so