Confusing range of a Relation.

Okay. So our assignment is to get the domain, range, intercepts, etc. of the relation (also a function but not expressed as one)

. I didn't have a problem at all till I realize that I got

(I EXCLUDED ZERO because when I solved for x, y is in the DENOMINATOR) as the range and have an x-intercept

which is a contradiction with the range.

Now, it leaves me with a dilemma because I can't include zero in the range because x will be undefined (at least if you use quadratic formula by manipulating the given equation which I think alters its nature I presume), and I can't just simply remove the x-intercept because of the same reason.

Here's my question, do I include zero in the range OR remove the x-intercept OR just leave my answer as it is.

And please explain why.

Re: Confusing range of a Relation.

It seems to me that and , your x-intercept is correct. Include y=0 in the range as it gives a corresponding x-value.

What about when ?

Re: Confusing range of a Relation.

Quote:

Originally Posted by

**pickslides** It seems to me that

Huh? Do you mean that the range is all real numbers? I think you must recheck it (or maybe I'm the one who is wrong).

Re: Confusing range of a Relation.