3 - x = 1 - 2x - 5
x - 2 1 x + 2
The Answer: 5
2
No idea how to get there, please help.
Is this
$\displaystyle \frac{3 - x}{x - 2} = 1 - \frac{2x - 5}{x + 2}$
Note that you can get rid of the fractions if you multiply both sides by $\displaystyle (x + 2)(x - 2)$:
$\displaystyle (x + 2)(x - 2) \left ( \frac{3 - x}{x - 2} \right ) =(x + 2)(x - 2) \left ( 1 - \frac{2x - 5}{x + 2} \right )$
$\displaystyle (x + 2)(3 - x) = (x + 2)(x - 2) - (x - 2)(2x - 5)$
Can you do it from here?
-Dan