x^{2}y - 16y + 32 - 2x^{2} what i came up with so far is y(x^{2} - 16) + 32 - 2x^{2} y(x + 4)(x - 4) + 32 - 2x^{2 }
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Originally Posted by PaperStSoap x^{2}y - 16y + 32 - 2x^{2} what i came up with so far is y(x^{2} - 16) + 32 - 2x^{2} y(x + 4)(x - 4) + 32 - 2x^{2 } $\displaystyle \displaystyle \begin{align*} x^2y - 16y + 32 - 2x^2 &= x^2y - 2x^2 - 16y + 32 \\ &= x^2\left(y - 2\right) - 16\left(y - 2\right) \\ &= \left(y - 2\right)\left(x^2 - 16\right) \\ &= \left(y - 2\right)\left(x - 4\right)\left(x + 4\right) \end{align*}$
32 + 2x^2 = -2(-16 + x^2) = -2(x^2 - 16) = -2(x + 4)(x - 4) (y-2)(x+4)(x-4) is this right?
Originally Posted by PaperStSoap 32 + 2x^2 = -2(-16 + x^2) = -2(x^2 - 16) = -2(x + 4)(x - 4) (y-2)(x+4)(x-4) is this right? Didn't you read the post directly above this one?
i was actually typing that response before yours came up.
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