It seems there are times where its possible to arrive at different factoring results. For instance view this problem from the book:

Books Solution:

My Solution:

Both factoring results seem to be correct.

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- June 25th 2012, 11:26 AMallyourbass2212Factoring Result Different than Book Example?
It seems there are times where its possible to arrive at different factoring results. For instance view this problem from the book:

Books Solution:

My Solution:

Both factoring results seem to be correct. - June 25th 2012, 12:07 PMPlatoRe: Factoring Result Different than Book Example?
- June 25th 2012, 12:23 PMHallsofIvyRe: Factoring Result Different than Book Example?
In that case, I would say that " " is also not "factored completely"! The "complete" factoring would be .

Of course that's is specifically "factoring with integer coefficients". Without that restriction, we could also factor as .

Or as

There are, in fact, an infinite number of ways to factor that. Unfortunately, this text box is not large enough for me to show all of them! - June 25th 2012, 01:06 PMrichard1234Re: Factoring Result Different than Book Example?
Both are correct, but is more completely factored.

There are other examples of polynomials that have several different factorizations, all correct, but don't easily follow from another factorization. - June 25th 2012, 01:27 PMSorobanRe: Factoring Result Different than Book Example?
Hello, allyourbass2212!

Quote:

It seems there are times where its possible to arrive at different factoring results.

. . This is not true.

By definition, "factor" always means "factor**completely**".

Otherwise, we might have this disagreement.

Problem: factor 30.

And you could argue (forever) over who is right.

Actually:

. . and**none of you**factored 30.*completely*

- June 25th 2012, 10:09 PMProve ItRe: Factoring Result Different than Book Example?
To avoid confusing the OP, we should point out that in the context of THIS question, the book appears to be asking to factorise this particular expression COMPLETELY OVER THE RATIONALS.

The highest rational common factor of and is , that is why it has been taken out.

Notice that in your solution, there is still a rational common factor of 2 inside your brackets...