Thread: Factors...and more Factors

I hate factors > <

1. http://i23.tinypic.com/15wflw1.jpg
Is that correct?

2. http://i24.tinypic.com/mmx2di.jpg
Is that correct? Do I have to take it a step further somehow?

3. http://i24.tinypic.com/106yko7.jpg
I have no clue what to do here.

4. http://i23.tinypic.com/2ymi1qa.jpg
Aside from C and D making no sense. The correct answer would be either A or B but it's B because it's the only one factored right? Isn't A like some GCF factor thing.

5. http://i20.tinypic.com/29y17jl.jpg
Is this correct?

Work:
(r^2-4tr) + (3wr -12tw)
gcf:r gcf:3w
r(r-4t) + 3w(r-4t)
woot
=(r-4t)(r+3w)

6. http://i20.tinypic.com/ztca6g.jpg
4+3xy-6y-2x

(4-2x) + (3xy-6y)
2(2-x) + 3y(x-2)

so now (2-x) and (x-2) are inverse or whatnot so multiplying one side by -1 would make the one on the right -3y(2-x) or would I leave the 3y alone?

Edit: got (2-x)(2-3y)

Hello, fluffy_penguin!

Ya done good!

1) Factor: .

My answer: . . . . . Right!


2) Factor: .

My answer: . . . . . Correct!



3) Factor out the greatest common factor. Simiplify the factors.

Note the common factor: .

Factor it out: .

Simplify: .

4) Factor: .

Factor by grouping: .

Then: .

5. Factor:.

Is this correct?
. . . . Yes!

6. Factor: .

My work:


so now (2-x) and (x-2) are inverse or whatnot,
then I would make the right -3y(2-x) . . . . Good!

Then you have: .

Factor out: .


Another approach . . .

We have: .

Rearrange terms: .

Factor by grouping: .

Therefore: .

Thanks for the help.

I was going to ask for #3 how you got positive 3 but I seemed to understand it now, the - had to be Multiplied
to both the z and the -3.
(4z-3)[(z+4)-(z-3)]
then
(4z-3)[z+4-z+3]