Case B: yes.
Note that
Therefore,
Hi Friends,
Case A:
1, 3, 5, 7, 9.....
To find the Nth term for the above type of progression, the equation is:
Nth term = a + (n-1)d
where a = initial term
d = common difference
n = number of terms
Case B:
1, 2, 4, 7, 11, ....
My question is: Is there any general equation to find the Nth term for the above type of progression ?
Note that the common difference is variable but has a constant progressive rate i.e, 1,2,3,4,.... and iteself has a common difference of 1
Thanks in advance.
Regards.