# simplify expressiom

• June 10th 2012, 08:35 PM
zbest1966
simplify expressiom
1-(X+h) - 1-X
2+(X-H) 2-X
• June 10th 2012, 09:48 PM
Prove It
Re: simplify expressiom
Quote:

Originally Posted by zbest1966
1-(X+h) - 1-X
2+(X-H) 2-X

First of all, are you using h and H to represent the same thing? If so, be consistent, either use all "h" or all "H".

Next, is this your expression? \displaystyle \begin{align*} \frac{1 - (x + h)}{2 + (x - h)} - \frac{1 - x}{2 - x} \end{align*}?

Learning a little LaTeX would help everyone...
• June 11th 2012, 08:25 PM
zbest1966
Re: simplify expressiom
[1-(x-h)](2-x) - (1-x)[2+(x+h)]
2+(x+h) 2+x

my ans is x^-5
(2+x+h)(2+x)
• June 11th 2012, 08:26 PM
zbest1966
Re: simplify expressiom
im lost
• June 12th 2012, 05:14 AM
Reckoner
Re: simplify expressiom
Quote:

Originally Posted by zbest1966
[1-(x-h)](2-x) - (1-x)[2+(x+h)]
2+(x+h) 2+x

How did all the terms in the denominator become positive? And how did you get $x^{-5}?$
• June 12th 2012, 06:08 AM
zbest1966
Re: simplify expressiom
2x^2(x-1)
(2+x+h)(2+x)
• June 12th 2012, 06:47 AM
skeeter
Re: simplify expressiom
Quote:

Originally Posted by zbest1966
1-(X+h) - 1-X
2+(X-H) 2-X

you keep changing signs in subsequent posts ... I get the feeling that this original expression has more than one sign typo.

is this what you originally meant ???

$\frac{1-(x+h)}{2+(x+h)} - \frac{1-x}{2+x}$

if not, fix it so that maybe someone can provide you with meaningful guidance.
• June 12th 2012, 06:51 AM
zbest1966
Re: simplify expressiom
Yes thats the orginal problem
• June 12th 2012, 06:58 AM
Reckoner
Re: simplify expressiom
Quote:

Originally Posted by zbest1966
Yes thats the orginal problem

The work you showed in your last post is a good first step. Just keep going...

$\frac{1-(x+h)}{2+(x+h)} - \frac{1-x}{2+x}$

$=\frac{\left[1-(x+h)\right](2+x)}{\left[2+(x+h)\right](2+x)} - \frac{\left[2+(x+h)\right](1-x)}{\left[2+(x+h)\right](2+x)}$

$=\frac{\left[1-(x+h)\right](2+x)-\left[2+(x+h)\right](1-x)}{\left[2+(x+h)\right](2+x)}$

Are you able to do the multiplication?
• June 12th 2012, 07:04 AM
zbest1966
Re: simplify expressiom
i did that my ans

2x^2(x-1)
(2+x+h)(2+x)
• June 12th 2012, 07:13 AM
Reckoner
Re: simplify expressiom
Quote:

Originally Posted by zbest1966
i did that my ans

2x^2(x-1)
(2+x+h)(2+x)

That's not what I'm getting. It would be helpful if you showed the actual work you did to get that answer...

$\frac{\left[1-(x+h)\right](2+x)-\left[2+(x+h)\right](1-x)}{\left[2+(x+h)\right](2+x)}$

$=\frac{(2+x)-\left(x^2 + 2h + 2x + hx\right)-(2-2x)-\left(x - hx - x^2 + h\right)}{\left[2+(x+h)\right](2+x)}$

$=\frac{2+x-x^2-2h-2x-hx-2+2x-x+hx+x^2-h}{\left[2+(x+h)\right](2+x)}$

Now combine like terms.
• June 12th 2012, 07:18 AM
zbest1966
Re: simplify expressiom
Thank you, that was a killer