x^{2}-x-12 . 3+x x^{2}-9 4-x ans (x-4)(3+X) (X-3)(4-X) THERE IN THE BOOK IS (3+X) (X-3)
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Originally Posted by zbest1966 THERE IN THE BOOK IS (3+X) (X-3) Note that . In general, . Edit: I didn't look too closely at the book's answer, but the other two posters are correct when they say that it is wrong.
Last edited by Reckoner; June 10th 2012 at 08:03 AM.
Originally Posted by zbest1966 x^{2}-x-12 . 3+x x^{2}-9 4-x ans (x-4)(3+X) (X-3)(4-X) THERE IN THE BOOK IS (3+X) (X-3) Both your answer and the book's answer are wrong.
Originally Posted by zbest1966 x^{2}-x-12 . 3+x x^{2}-9 4-x ans (x-4)(3+X) (X-3)(4-X) THERE IN THE BOOK IS (3+X) (X-3) I disagree the answer in the textbook. It should be .
if you a negative on the top you must put a negative on the bottom.
Originally Posted by zbest1966 if you a negative on the top you must put a negative on the bottom. Not true. What I have written is correct, I've just written so that you have a common factor you can cancel.
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